Math problem

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Grizzly
Posts: 2014
Joined: Fri Mar 16, 2018 9:06 am

Re: Math problem

#31 Post by Grizzly » Thu May 23, 2019 1:44 am

dougedwards wrote:
Wed May 22, 2019 11:45 am
The total of (3) pairs of boots = 30

We would have to speculate that each boot would carry a numerical equivalent of (5) since three pairs equals six units times (5) = 30.
Same goes with what looks like binoculars but must actually be monoculars with a numerical equivalent of (2) ea.

But the little guy with the pair of boots on and what appears to be monoculars under his arm is a stretch.

Doug
so is the sequence of +++'s when in the last row they sneak in a x

Then there is some math rule someone mentioned that - if I'm right - tells you to multiply before you add. That is the only way to come up with the right answer of 43
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Nock
Posts: 551
Joined: Mon Aug 20, 2018 8:03 am

Re: Math problem

#32 Post by Nock » Thu May 23, 2019 5:17 am

Grizzly wrote:
Thu May 23, 2019 1:44 am
dougedwards wrote:
Wed May 22, 2019 11:45 am
The total of (3) pairs of boots = 30

We would have to speculate that each boot would carry a numerical equivalent of (5) since three pairs equals six units times (5) = 30.
Same goes with what looks like binoculars but must actually be monoculars with a numerical equivalent of (2) ea.

But the little guy with the pair of boots on and what appears to be monoculars under his arm is a stretch.

Doug
so is the sequence of +++'s when in the last row they sneak in a x

Then there is some math rule someone mentioned that - if I'm right - tells you to multiply before you add. That is the only way to come up with the right answer of 43
Yep.
Happiness is a tight chain!

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